-16x^2+17x+6.5=0

Solution for -16x^2+17x+6.5=0 equation:

-16x^2+17x+6.5=0

a = -16; b = 17; c = +6.5;
Δ = b2-4ac
Δ = 172-4·(-16)·6.5
Δ = 705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{705}}{2*-16}=\frac{-17-\sqrt{705}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{705}}{2*-16}=\frac{-17+\sqrt{705}}{-32}
$